A can do half as much work as B in 3/4th of the time. Together they can finish a piece of work in 18 days. In how many days will B alone finish the work ?
Answer & explanation
Correct answer: option 3
Let B takes x days to complete the work
According to question ,
time taken by A to complete the work = 2 × \(\frac{3x}{4}\) = \(\frac{3x}{2}\)
Together they can finish a piece of work in 18 days .
( A + B )'s 1 day work = \(\frac{1}{18}\)
Now , \(\frac{1}{x}\) + \(\frac{2}{3x}\) = \(\frac{1}{18}\)
x = \(\frac{18 \;× \;5}{3}\) = 30
Hence B takes 30 days to complete the work