A monkey climbs on 57 m high greased pole. In 1st minute he climbs 10 meter and in 2nd minute he comes down by 2 meter. If he climbs in such a manner in what time will he comes to the height of the pole.

12 min 54 sec

1st min → 10 m (up)

2nd min → 2 m (down)

----------------------------

2 min → 8 meter (up)

   ⇓ x6          ⇓ x6

12 min        48 (meter)

Remaining height = 9m

Next min jump = 10 m

Time to reach height of the pole= \(\frac{9}{10}\)   

12 min +  \(\frac{9}{10}\) → 12 min 54 sec