A monkey climbs on 57 m high greased pole. In 1st minute he climbs 10 meter and in 2nd minute he comes down by 2 meter. If he climbs in such a manner in what time will he comes to the height of the pole.
Answer & explanation
Correct answer: option 3
1st min → 10 m (up)
2nd min → 2 m (down)
----------------------------
2 min → 8 meter (up)
⇓ x6 ⇓ x6
12 min 48 (meter)
Remaining height = 9m
Next min jump = 10 m
Time to reach height of the pole= \(\frac{9}{10}\)
12 min + \(\frac{9}{10}\) → 12 min 54 sec