The least six digits numbers which is divided by 4, 12, 15, 20 leaves in each case same remainder 2 be N. Sum of the digits in N is:
Answer & explanation
Correct answer: option 2
L.C.M. of 4, 6, 10 and 15 = 60
Least number of six digits = 100000
Dividing 100000 by 60 we get remainder = 40
∴ Least number of six digits divisible by 4, 6, 10 and 15
= 100000 + (60 - 40) = 100020
∴ N = 100020 + 2 = 100022
∴ Sum of digits in N = 1 + 0 + 0 + 0 + 2 + 2 = 5