Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Wave Optics

Question:

What is the resolving power of a telescope whose objective lens has an aperture of 1.0 m for the wavelength of light 500 nm?

Options:

1.64 x \( {10 }^{6 } \)

3.28 x \( {10 }^{6 } \)

1.64 x \( {10 }^{5 } \)

3.28 x \( {10 }^{5 } \)

Correct Answer:

1.64 x \( {10 }^{6 } \)

Explanation:

D = 1.0 m

λ = 500 nm

Use :

Resolving power = \(\frac{1}{θ}\) = \(\frac{D}{1.22 λ}\)