A battery of emf 10 V and internal resistance \( 3\,\Omega \) is connected to an external resistor. If the current in the circuit is 0.5 A, then the voltage drop across the external resistor will be
Answer & explanation
Correct answer: option 1
The correct answer is Option (1) → \( 8.5\,\mathrm{V} \)
The voltage across the external resistor is the terminal voltage of the battery: the emf minus the drop across the internal resistance, \( V = \varepsilon - I r \).
\( \displaystyle V = 10 - (0.5 \times 3) = 10 - 1.5 = 8.5\,\mathrm{V} \)
Note: This question is from NCERT (2026-27). NTA sets numerical questions from NCERT too, so do not ignore NCERT while practising numericals.
NCERT (2026-27):
Exercises – …
