If the value of sec B + tan B = r, then the value of sec B - tan B is equal to:
Answer & explanation
Correct answer: option 2
Given :-
sec B + tan B = r
We know ,
sec² B - tan² B = 1
( sec B + tan B ) . ( sec B - tan B ) = 1
( sec B - tan B ) = \(\frac{1 }{( sec B + tan B ) }\)
As, sec B + tan B = r
So , ( sec B - tan B ) = \(\frac{1 }{r }\)