A die is thrown three times. If the first throw is a five, the probability of getting 14 as the sum is
Answer & explanation
Correct answer: option 1
The correct answer is Option (1) → $\frac{1}{9}$
Given that the first throw is $5$.
To get total sum $14$, the sum of the second and third throws must be
$14-5=9$
Possible ordered pairs $(x,y)$ such that $x+y=9$ where $x,y\in\{1,2,3,4,5,6\}$ are
$(3,6),(4,5),(5,4),(6,3)$
Total possible outcomes for second and third throws $=6\times6=36$
Favourable outcomes $=4$
Probability $=\frac{4}{36}$
$=\frac{1}{9}$