The internal resistance of primary cell is 3 Ω. It generates a current of 0.3 A in an external resistance of 22 Ω. The rate at which chemical energy is consumed in providing the current is:
Answer & explanation
Correct answer: option 1
The correct answer is Option (1) → $2.25 Js^{-1}$
Electrical Power (P) is -
$P=I^2R_{total}$
$=(0.3)^2(3+22)=2.25W$