Practicing Success
The internal resistance of primary cell is 3 Ω. It generates a current of 0.3 A in an external resistance of 22 Ω. The rate at which chemical energy is consumed in providing the current is: |
$2.25 Js^{-1}$ $2.25 J$ $2.5 Js^{-1}$ $2.5 J$ |
$2.25 Js^{-1}$ |
The correct answer is Option (1) → $2.25 Js^{-1}$ |