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The internal resistance of primary cell is 3 Ω. It generates a current of 0.3 A in an external resistance of 22 Ω. The rate at which chemical energy is consumed in providing the current is: |
$2.25 Js^{-1}$ $2.25 J$ $2.5 Js^{-1}$ $2.5 J$ |
$2.25 Js^{-1}$ |
The correct answer is Option (1) → $2.25 Js^{-1}$ Electrical Power (P) is - $P=I^2R_{total}$ $=(0.3)^2(3+22)=2.25W$ |
