If $x\left[\begin{array}{l}5 \\ 2\end{array}\right]+y\left[\begin{array}{l}-3 \\ -2\end{array}\right]=\left[\begin{array}{c}5 \\ -3\end{array}\right]$, then value of x and y will be |
$-\frac{19}{4}, \frac{25}{4}$ $\frac{19}{14},-\frac{25}{4}$ $\frac{25}{4}, \frac{19}{4}$ $\frac{19}{4}, \frac{25}{4}$ |
$\frac{19}{4}, \frac{25}{4}$ |
$x\begin{bmatrix}5\\2\end{bmatrix}+y\begin{bmatrix}-3\\-2\end{bmatrix}=\begin{bmatrix}5\\-3\end{bmatrix}.$ $5x-3y=5.$ $2x-2y=-3.$ $x-y=-\frac{3}{2}.$ $y=x+\frac{3}{2}.$ $5x-3\left(x+\frac{3}{2}\right)=5.$ $2x-\frac{9}{2}=5.$ $2x=\frac{19}{2}.$ $x=\frac{19}{4}.$ $y=\frac{19}{4}+\frac{3}{2}=\frac{25}{4}.$ $x=\frac{19}{4},\;y=\frac{25}{4}.$ |