The correct relation for determining the molar mass of solute ($M_2$) using osmotic pressure measurement, is |
$M_2=\frac{w_2^2RT}{ПV}$ $M_2=\frac{w_2RT}{ПV}$ $M_2=\frac{w_2RT^2}{ПV}$ $M_2=\frac{w_2RT}{П\sqrt{V}}$ |
$M_2=\frac{w_2RT}{ПV}$ |
The correct answer is Option (2) → $M_2=\frac{w_2RT}{ПV}$ Osmotic pressure is a colligative property that depends on the number of solute particles present in the solution. The fundamental relation for osmotic pressure is Π = CRT where Π = osmotic pressure C = molar concentration of solution R = universal gas constant T = absolute temperature Molar concentration can be written as C = n / V where n is the number of moles of solute and V is the volume of the solution. Number of moles of solute is n = w₂ / M₂ where w₂ = mass of solute M₂ = molar mass of solute Substituting in the osmotic pressure equation: Π = (w₂ / M₂V) RT Rearranging to obtain molar mass: M₂ = (w₂RT) / (ΠV) Thus the correct relation for determining molar mass using osmotic pressure is M₂ = (w₂RT) / (ΠV)
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