In a circle, AB and CD are two diameters that are perpendicular to each other.  Find the length of the chord AC?

\(\frac{CD}{\sqrt {2}}\) 2\(\sqrt{2}\) CD 2CD \(\sqrt {2}\) CD

\(\frac{CD}{\sqrt {2}}\)

Let, CO = OA = 2r AC = r\(\sqrt {2}\) AC = \(\frac{CD}{2}\) × \(\sqrt {2}\)         (CD = 2r) AC = \(\frac{CD}{\sqrt {2}}\)