Let f : [-10,10] → R, where f(x) = sin x + [x2/a] be an odd function. Then set of values of parameter ‘a’ is/are:

(-10, 10) - {0} (0, 10) [100, ∞) (100, ∞)

(100, ∞)

Since f(x) is an odd function, $[\frac{x^2}{a}]= 0$ for all x ∈ [-10, 10] ⇒ $0≤ \frac{x^2}{a}< 1$ for all x ∈ [-10, 10] ⇒ a > 100. Hence (D) is the correct answer.