Two trains are moving in the opposite direction at the speed of 48 km/hr and 60 km/hr respectively. The time taken by the slower train to cross a man sitting in the faster train is 12 seconds. What is the length of the slower train?
Answer & explanation
Correct answer: option 4
Relative speed = 60 + 48 = 108 km/h
108 km/h = 108 × \(\frac{5}{18}\) m/sec = 30 m/sec
Distance = Speed × Time
Total distance = 30 × 12 = 360 m