Two trains are moving in the opposite direction at the speed of 48 km/hr and 60 km/hr respectively. The time taken by the slower train to cross a man sitting in the faster train is 12 seconds. What is the length of the slower train?

480 metres 720 metres 180 metres 360 metres

360 metres

Relative speed = 60 + 48 = 108 km/h 108 km/h = 108 × \(\frac{5}{18}\) m/sec = 30 m/sec Distance = Speed × Time Total distance = 30 × 12 = 360 m