Practicing Success
Practicing Success
CUET Preparation Today
If $A=\begin{bmatrix} 2&1 & 3 \\4 & 6 &1 \end{bmatrix}$ and $B=\begin{bmatrix}2 & 4\\3 & -2\\ 6& 5\end{bmatrix}, $ then |
Only AB is defined Only BA is defined AB and BA both are defined AB and BA both are not defined |
AB and BA both are defined |
