The value of \(\int_{\frac{\pi}{6}}^{\frac{\pi}{3}}\frac{dx}{1+\sqrt{\tan x}}\) is
Answer & explanation
Correct answer: option 3
Use \(\int_{a}^{b}f\left(x\right) dx=\int_{a}^{b}\left(a+b-x\right)dx\)
The value of \(\int_{\frac{\pi}{6}}^{\frac{\pi}{3}}\frac{dx}{1+\sqrt{\tan x}}\) is
Correct answer: option 3
Use \(\int_{a}^{b}f\left(x\right) dx=\int_{a}^{b}\left(a+b-x\right)dx\)