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CUET
General Test
Numerical Ability
The least number which is divided by 4, 6, 8, 12 & 15 leaves a remainder 3 in each case is:
121
122
123
124
LCM of 4, 6, 8, 12, 15 = 120
The remainder is 3 in each case, then the number will be 120 + 3 = 123