If A and B are two matrices such that $AB = A$and $BA=B$, then $A^2+ B^2$ is equal to
Answer & explanation
Correct answer: option 3
Proceeding as in Example 2, we have
We have,
$A^2 = AA$
$⇒A^2 (AB) A$ $[∵ AB=A]$
$⇒A^2 = A (BA)$
$⇒A^2 = AB$ $[∵ BA=B]$
$⇒A^2 = A$ $[∵ AB = A]$
and,
$B^2 = BB$
$⇒B^2 = (BA) B$ $[∵ BA =B]$
$⇒B^2=B (AB)$
$⇒B^2=BA$ $[∵ AB = A]$
$⇒B^2 = B$ $[∵ BA =B]$
Now, we have
$A^2 = A$ and $B^2 = B$
$∴A^2+ B^2=A+B$