Practicing Success
The population of a town is 8000. It increases by 10% during the first year and by 20% during the second year. What will be the population after two years? |
10560 13560 15560 11560 |
10560 |
10% = \(\frac{1}{10}\) 20% = \(\frac{1}{5}\) New population = 8000 × \(\frac{11}{10}\) × \(\frac{6}{5}\) = 10560 |