Find equation of a line through the poin

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Target Exam

CUET

Subject

-- Mathematics - Section B1

Chapter

Vectors

Question:

Find equation of a line through the point (-2, 1, 3) and parallel to the line $\frac{x-2}{4}=\frac{y+3}{-3},z=-2$

Options:

$\frac{x+2}{4}=\frac{y-1}{-3},z=3$

$\frac{x+2}{4}=\frac{y-1}{-3},z=-3$

$\frac{x+2}{4}=\frac{y-1}{3}=\frac{z-3}{1}$

$\frac{x+2}{4}=\frac{y-1}{3}=\frac{z+3}{1}$

Correct Answer:

$\frac{x+2}{4}=\frac{y-1}{-3},z=3$

Explanation:

Point $P(-2,1,3)$ parallel to $\frac{x-2}{4}=\frac{y+3}{-3},z=-2$

Parallel vector is $4\hat i-3\hat j+0\hat k$

Equation of give line is $\frac{x+2}{4}=\frac{y-1}{-3},z=3$