Find equation of a line through the point (-2, 1, 3) and parallel to the line $\frac{x-2}{4}=\frac{y+3}{-3},z=-2$
Answer & explanation
Correct answer: option 1
Point $P(-2,1,3)$ parallel to $\frac{x-2}{4}=\frac{y+3}{-3},z=-2$
Parallel vector is $4\hat i-3\hat j+0\hat k$
Equation of give line is $\frac{x+2}{4}=\frac{y-1}{-3},z=3$