A sum (in ₹) is distributed between A, B and in the ratio 9 : 6 : 11. If A gives ₹500 from his share to C, the ratio of shares of A, B and C becomes 4 : 3 : 6. What is the sum of shares(in ₹) of B and C, in the beginning?

₹8,500

ratio of A, B and C = 9 : 6 : 11

According to the question,

\(\frac{9x-500}{11x+500}\) = \(\frac{4}{6}\) = \(\frac{2}{3}\)

3(9x – 500) = 2(11x + 500)

 27x – 1500 = 22x + 1000

 27x – 22x = 1000 + 1500

 5x = 2500

 x = 500

Sum of share of B and C = 6x + 11x = 17x

= 17 × 500 = 8500