If A = \(\begin{bmatrix}3 & 6\\-1 & 2 \end{bmatrix}\), then what can be said about 12\( { A }^{ -1 } \)?

12\( { A }^{ -1 } \) = 12 (adj A) 12\( { A }^{ -1 } \) = 3 (adj A) 12\( { A }^{ -1 } \) = (adj A) 12\( { A }^{ -1 } \) = 4 (adj A)

12\( { A }^{ -1 } \) = (adj A)

\( { A }^{ -1 } \) =\(\frac{adj A}{|A|}\) But |A| = 12 So, \( { A }^{ -1 } \) =\(\frac{adj A}{12}\) 12 \( { A }^{ -1 } \) = 12 \(\frac{adj A}{12}\)                                 (adj A)