Given: Molecular weight of NaOH = 40 g/mol Mass of NaOH = 5 g Volume of the solution = 500 mL = 0.500 L
Step 1: Calculate the number of moles of NaOH. Number of moles of NaOH = \(\frac{\text{Mass of NaOH}}{\text{Molecular weight of NaOH}} = \frac{5 \text{ g}}{40 \text{ g/mol}} = 0.125 \text{ moles}\)
Step 2: Calculate the molarity (M) of the solution. Molarity (M) = \(\frac{\text{Number of moles of NaOH}}{\text{Volume of solution in liters}} = \frac{0.125 \text{ moles}}{0.500 \text{ L}} = 0.25 \text{ M}\) |