If $x^2 + 1 - 2x = 0, 2x = 0, x > 0, $ then $x^2 (x^2 - 2)$ = ________.

1 $\sqrt{2}$ -1 0

-1

If $x^2 + 1 - 2x = 0, 2x = 0, x > 0, $ then $x^2 (x^2 - 2)$ = ? Put the value of x = 1 ( This value will satisfy the given equation ) $x^2 (x^2 - 2)$ = $1^2 (1^2 - 2)$ = -1