If x^2 + 1 - 2x = 0, 2x = 0, x > 0, then x^2 (x^2 - 2) = ________.

If $x^2 + 1 - 2x = 0, 2x = 0, x > 0, $

then $x^2 (x^2 - 2)$ = ?

Put the value of x = 1 ( This value will satisfy the given equation )

$x^2 (x^2 - 2)$ = $1^2 (1^2 - 2)$ = -1