A 50 cm long air core solenoid has a 2 cm radius and 500 turns. The self-inductance of the solenoid would be (given $μ_0 = 4 × 10^{-7} T m\, A^{-1}$ and $\pi^2 = 10$) |
$5.0 × 10^{-4} H$ $6.0 × 10^{-4} H$ $8.0 × 10^{-4} H$ $0.1 × 10^{-4} H$ |
$8.0 × 10^{-4} H$ |
The correct answer is Option (3) → $8.0 × 10^{-4} H$ |