Manu sells two articles, first at 15% loss and 2nd at 19% profit. During the transaction he bears a loss of ₹90. If he sells both article at same price then find the cost price of 2nd article.

₹4500

I :  15% = \(\frac{3}{20}\)       

II:  19% = \(\frac{19}{100}\)

          CP   :   L/P   :   S.P.

I:      [ 20   :   03    :    17 ]  × 7        (*to make S.P. same)

I:       140  :   -21   :    119

II:      100  :  +19   :    119

                    - 2R  (Loss)

ATQ,

⇒ 2R = 90 (given)

⇒ 1R = 45

⇒ C.P of 2nd article = 100R = 100 × 45 = 4500/-