Manu sells two articles, first at 15% loss and 2nd at 19% profit. During the transaction he bears a loss of ₹90. If he sells both article at same price then find the cost price of 2nd article.
Answer & explanation
Correct answer: option 3
I : 15% = \(\frac{3}{20}\)
II: 19% = \(\frac{19}{100}\)
CP : L/P : S.P.
I: [ 20 : 03 : 17 ] × 7 (*to make S.P. same)
I: 140 : -21 : 119
II: 100 : +19 : 119
- 2R (Loss)
ATQ,
⇒ 2R = 90 (given)
⇒ 1R = 45
⇒ C.P of 2nd article = 100R = 100 × 45 = 4500/-