If the area of the trapezium, whose parallel sides are 6 cm and 10 cm is 32 sq. cm, what will be the distance between the parallel sides?
Answer & explanation
Correct answer: option 3
Area of the trapezium:
Area of a trapezium = \(\frac{\text{Sum of parallel sides}}{2 }\) * height
32 = \(\frac{\text{ 6 + 10}}{2 }\) * height
32 = \(\frac{\text{ 16}}{2 }\) * height
32 = 8 x height
height = 4 cm
Thus, we can say that the distance between the parallel sides is 4 cm