If the area of the trapezium, whose parallel sides are 6 cm and 10 cm is 32 sq. cm, what will be the distance between the parallel sides?

4 cm

Area of the trapezium:

Area of a trapezium = \(\frac{\text{Sum of parallel sides}}{2 }\) * height

32 = \(\frac{\text{ 6 + 10}}{2 }\) * height

32 = \(\frac{\text{ 16}}{2 }\) * height

32 = 8 x height

height = 4 cm

Thus, we can say that the distance between the parallel sides is 4 cm