In ΔABC, D and E are the points on the sides Ab and AC, respectively such that ∠AED = ∠ABC. If AE = 6 cm, BD = 2 cm, DE = 3 cm and BC = 5 cm, then (AB + AC) is equal to: |
$\frac{86}{3}$ cm $\frac{49}{3}$ cm $\frac{50}{3}$ cm $\frac{70}{3}$ cm |
$\frac{70}{3}$ cm |