The prices and quantities of some commodities are given below :
Given that $∑p_0q_0= 6600, $ and $∑p_1q_1=12-10.$ Based on the above information the value of x is : | ||||||||||||||||||||||||||||||||||
80 100 90 110 |
100 |
The correct answer is Option (2) → 100 $∑p_0q_0= 6600$ $140(10)+400(7)+x(6)+125(8)+200(4)=6600$ $⇒6000+6x=6600$ $⇒6x=600$ $⇒x=100$ |