A person invested ₹20000 in a mutual fund in year 2018. The value of the mutual fund increased to ₹32000 in year 2023. The compound annual growth rate of his investment is: [Given that $(1.6)^{1/5}= 1.098$] |
9.8% 8.7% 10% 7.8% |
9.8% |
The correct answer is Option (1) → 9.8% Initial value $=20000$ Final value $=32000$ Number of years $=5$ Formula for CAGR $\text{CAGR}=\left(\frac{\text{Final value}}{\text{Initial value}}\right)^{\frac{1}{n}}-1$ $=\left(\frac{32000}{20000}\right)^{\frac{1}{5}}-1$ $=(1.6)^{\frac{1}{5}}-1$ Given $(1.6)^{\frac{1}{5}}=1.098$ $\text{CAGR}=1.098-1=0.098$ $=9.8\%$ The compound annual growth rate is $9.8\%$. |