Let $f(x)=\left\{\begin{matrix} 2x-1, & x< 1\\1, & x=1\\x^2, &x> 1\end{matrix}\right.$
then at $x=1 $
Answer & explanation
Correct answer: option 3
The correct answer is Option (3) → f(x) is continuous
$\lim\limits_{x→1^-}2x-1=1$
$f(1)=1$
$\lim\limits_{x→1^+}x^2=1$
⇒ f is continuous function