Practicing Success
Practicing Success
CUET Preparation Today
Let $f(x)=\left\{\begin{matrix} 2x-1, & x< 1\\1, & x=1\\x^2, &x> 1\end{matrix}\right.$ then at $x=1 $ |
f(x) is continuous from left only f(x) is continuous from right only f(x) is continuous f(x) has removable discontinuity |
f(x) is continuous |
The correct answer is Option (3) → f(x) is continuous $\lim\limits_{x→1^-}2x-1=1$ $f(1)=1$ $\lim\limits_{x→1^+}x^2=1$ ⇒ f is continuous function |
