Practicing Success
Practicing Success
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If the mean and variance of a binomial distribution are $\frac{5}{6}$ and $\frac{25}{36}$ respectively. They value of $P(X=2)$ is : |
${^5C}_3\left(\frac{1}{6}\right)^3\left(\frac{5}{6}\right)^2$ ${^5C}_1\left(\frac{5}{6}\right)^3\left(\frac{1}{6}\right)^2$ ${^5C}_1\left(\frac{5}{6}\right)^2\left(\frac{1}{6}\right)^3$ ${^5C}_2\left(\frac{1}{6}\right)^2\left(\frac{5}{6}\right)^3$ |
${^5C}_2\left(\frac{1}{6}\right)^2\left(\frac{5}{6}\right)^3$ |
