Target Exam

CUET

Subject

-- Applied Mathematics - Section B2

Chapter

Numbers, Quantification and Numerical Applications

Question:

600 g of Jaggery Syrup has 40% jaggery in it, how much jaggery should be added to make it 50% in the syrup?

Options:

100 gm

80 gm

110 gm

120 gm

Correct Answer:

120 gm

Explanation:

The correct answer is Option (4) →  120 gm

$\text{Initial jaggery} = 40\% \text{ of } 600 = 240 \text{ g}$

$\text{Let } x \text{ g jaggery be added}$

$\text{New jaggery} = 240 + x$

$\text{Total mixture} = 600 + x$

$\frac{240 + x}{600 + x} = \frac{1}{2}$

$2(240 + x) = 600 + x$

$480 + 2x = 600 + x$

$x = 120$

The jaggery to be added is $120$ g.