A bar magnet oscillates with time period 'T' in a uniform magnetic field B. Now the magnet is cut into two equal parts by cutting it perpendicular to its length. The time period of each part in the same magnetic field:

$\frac{T}{2}$ $2 T$ $\frac{T}{4}$ $\frac{T}{2 \sqrt{2}}$

$\frac{T}{2}$

The correct answer is Option (1) → $\frac{T}{2}$