Practicing Success
Practicing Success
CUET Preparation Today
$\frac{x^2(x-4)^2}{(x+4)^2-4 x} \div \frac{\left(x^2-4 x\right)^3}{(x+4)^2} \times \frac{64-x^3}{16-x^2}$ is equal to |
$\frac{x-4}{x+4}$ $\frac{x+4}{x(4-x)}$ $\frac{x+4}{x(x-4)}$ $\frac{x+4}{x-4}$ |
$\frac{x+4}{x(x-4)}$ |
