Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Atoms

Question:

The extreme wavelengths of Paschen series are

Options:

0.365 µm and 0.565 µm

0.818 µm and 1.89 µm

1.45 µm and 4.04 µm

2.27 µm and 7.43 µm

Correct Answer:

0.818 µm and 1.89 µm

Explanation:

ln Paschen series $\frac{1}{\lambda_{\max }}=R\left[\frac{1}{(3)^2}-\frac{1}{(4)^2}\right]$

$\Rightarrow \lambda_{\max }=\frac{144}{7 R}=\frac{144}{7 \times 1.1 \times 10^7}=1.89 \times 10^{-6} \mathrm{~m}=1.89 \mu \mathrm{m}$

Similarly $\lambda_{\min }=\frac{9}{R}=\frac{9}{1.1 \times 10^7}$ = 0.818 µm