If the seventh day of a month is three days earlier than a Friday, what day will be the nineteenth day of the same month?
Answer & explanation
Correct answer: option 4
The correct answer is Option (4) → Sunday
Step 1: Find the 7th day
The problem states that the 7th day is "three days earlier than a Friday."
- 1 day earlier than Friday is Thursday.
- 2 days earlier than Friday is Wednesday.
- 3 days earlier than Friday is Tuesday.
So, the 7th day is a Tuesday.
Step 2: Find the 19th day
Since the 7th is a Tuesday, we can add weeks (7 days) to find subsequent Tuesdays:
- 7th = Tuesday
- 14th (7 + 7) = Tuesday
Now, we count forward from the 14th to the 19th:
- 15th = Wednesday
- 16th = Thursday
- 17th = Friday
- 18th = Saturday
- 19th = Sunday
Alternatively, the difference between the days is $19 - 7 = 12$ days.
$12 \text{ days} = 1 \text{ week and } 5 \text{ odd days}$.
Tuesday + 5 days = Sunday.