What is the EMF of the following cell? Fe|Fe2+ (0.6M) || Sn2+(0.2M)|Sn    ; EoFe2+/Fe = -0.44 V,  EoSn2+/Sn = 0.14 V

0.566 V 0.466 V 0.366 V 0.266 V

0.566 V

Eocell = EoSn2+/Sn - EoFe2+/Fe = 0.14 - (-0.44) = 0.14 + 0.44 = 0.58 V Ecell = Eocell - \(\frac{0.059}{2}\)log\(\frac{[Fe^{2+}]}{[Sn^{2+}]}\) Ecell = 0.58 - 0.0295log\(\frac{[0.6]}{[0.2]}\) Ecell = 0.58 - 0.0295 x log3 Ecell = 0.58 - 0.0295 x 0.47 = 0.566 V