Target Exam

CUET

Subject

-- Applied Mathematics - Section B2

Chapter

Financial Mathematics

Question:

Mr Mohan invested ₹5000 in a fund at the beginning of year 2018 and by the end of year 2018 his investment was worth ₹9000. Next year market crashed and he lost ₹ 3000 and ending up with ₹6000 at the end of year 2019. Next year i.e. 2020 he gained ₹4500 and ending up with ₹10500 at the end of the year. Find CAGR of his investment.

Options:

24%

28%

26%

32%

Correct Answer:

28%

Explanation:

The correct answer is option (2) : 28%

Given $P.V. = ₹5000$

$F.V. =₹10500$

$n= 3\, years $

So, CAGR $=\left(\frac{10500}{5000}\right){1/3}-1$

$= (2.1)^{1/3}-1$

Let $x = (2.1)^{1/3}$

$log\, x=\frac{1}{3}log (2.1)$

$=\frac{1}{3}×0.3222$

$= 0.1074$

$x= antiog \, 0.1074$

$= 1.280 $

So, CAGR = $ 1.280-1 = 0.280$

Hence, CAGR $= 0.280 × 100$%

= 28%