Mr Mohan invested ₹5000 in a fund at the beginning of year 2018 and by the end of year 2018 his investment was worth ₹9000. Next year market crashed and he lost ₹ 3000 and ending up with ₹6000 at the end of year 2019. Next year i.e. 2020 he gained ₹4500 and ending up with ₹10500 at the end of the year. Find CAGR of his investment. |
24% 28% 26% 32% |
28% |
The correct answer is option (2) : 28% Given $P.V. = ₹5000$ $F.V. =₹10500$ $n= 3\, years $ So, CAGR $=\left(\frac{10500}{5000}\right){1/3}-1$ $= (2.1)^{1/3}-1$ Let $x = (2.1)^{1/3}$ $log\, x=\frac{1}{3}log (2.1)$ $=\frac{1}{3}×0.3222$ $= 0.1074$ $x= antiog \, 0.1074$ $= 1.280 $ So, CAGR = $ 1.280-1 = 0.280$ Hence, CAGR $= 0.280 × 100$% = 28% |