An aromatic compound (A) on treatment with aqueous ammonia and heating forms compound (B) which on heating with Br₂ and KOH forms a compound (C) of molecular formula C₆H₇N.  

Identify (C) from the given reaction. 

None of the above 

The correct answer is option 4- None of the above

1. A is likely benzoyl chloride or benzoic acid, which on reacting with aqueous ammonia and heating gives benzamide (B).

2. Compound B (benzamide) when heated with Br₂ and KOH undergoes Hofmann bromamide reaction, which removes the carbonyl carbon and converts the amide into an amine.

   • So, C = aniline (C₆H₅NH₂), which matches the molecular formula C₆H₇N.

Final Conclusion:

• The correct answer should be Aniline.

• However, Aniline is not among the options listed.

• Option 1: Benzamine is incorrect, as this is not a proper IUPAC name and is sometimes mistakenly used for benzylamine (C₆H₅CH₂NH₂), which has a different structure.

• Correct answer is thus Option 4: None of the above, as none of the names match Aniline.