The order of reaction will be if the value of rate constant is \(7.195 × 10^{-4} mol^{-3}L^3s^{-1}\)
Answer & explanation
Correct answer: option 4
The correct answer is Option (4) → 4
For a reaction of order n, rate = k[A]n, so
\( k = \displaystyle\frac{\text{rate}}{[A]^n} = \displaystyle\frac{\text{mol L}^{-1}\,\text{s}^{-1}}{(\text{mol L}^{-1})^n} = (\text{mol L}^{-1})^{1-n}\,\text{s}^{-1} = \text{mol}^{1-n}\,\text{L}^{n-1}\,\text{s}^{-1} \)
Zero order: mol L−1 s−1; first order: s−1; second order: mol−1 L s−1; third order: mol−2 L2 s−1.
The given unit is mol−3 L3 s−1:
1 − n = −3 ⇒ n = 4 (check: Ln−1 = L3)
So the reaction is of fourth order.
NCERT (2026-27 edition):
Units of Rate Constant – …
