Why does colour of $KMnO_4$ disappear when oxalic acid is added to its solution in acidic medium?

${MnO_4}^-$ is reduced to $Mn^{2+}$ which is colourless

The correct answer is Option (4) → ${MnO_4}^-$ is reduced to $Mn^{2+}$ which is colourless

• In acidic medium, potassium permanganate (KMnOâ‚„) acts as a strong oxidizing agent.
• When oxalic acid (Hâ‚‚Câ‚‚Oâ‚„) is added:

$2MnO_4^- + 5H_2C_2O_4 + 6H^+ \rightarrow 2Mn^{2+} + 10CO_2 + 8H_2O$

• $MnO_4^-$ (purple) is reduced to $Mn^{2+}$ (colourless), causing the disappearance of the purple color.

Hence, the correct option is $MnO_4^-$ is reduced to $Mn^{2+}$ which is colourless.