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The half-life period of a first order reaction is 15 minutes. What is the amount of substance left after one hour?
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\(\frac{1}{4}\) of the original amount \(\frac{1}{16}\) of the original amount \(\frac{1}{32}\) of the original amount \(\frac{1}{8}\) of the original amount |
\(\frac{1}{16}\) of the original amount |
Since : t1/2 = 15 min. No. of half lives = \(\frac{60}{15}\) = 4 Amount of substance left after one hour = \(\frac{A_0}{2^n}\) = \(\frac{A_0}{2^4}\) = \(\frac{A_0}{16}\) |
