A parallel plate capacitor having cross - sectional area 'A' and separated by distance 'd' is filled by copper plate of thickness b. It's capacitance is:

$\frac{\varepsilon_0 A}{d-b}$

The correct answer is Option (2) → $\frac{\varepsilon_0 A}{d-b}$

Capacitance of parallel-plate capacitors, filled by copper plate of thickness 'b' is,

$C=\frac{ε_0A}{d-b}$

d = Seperation between plates

A = Plate area