A parallel plate capacitor having cross - sectional area 'A' and separated by distance 'd' is filled by copper plate of thickness b. It's capacitance is:
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → $\frac{\varepsilon_0 A}{d-b}$
Capacitance of parallel-plate capacitors, filled by copper plate of thickness 'b' is,
$C=\frac{ε_0A}{d-b}$
d = Seperation between plates
A = Plate area