Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Kinetic Theory

Question:

The ratio of pressure of the same gas in two containers is \(\frac{n_1T_1}{n_2T_2}\) where n1 and n2 are the number of moles and T1 and T2 are respective temperatures. If the two containers are now joined find the ratio of pressure to the temperature : 

Options:

\(\frac{P_1T_2 + P_2T_1}{2T_1T_2}\)

\(\frac{P_1T_1 + P_2T_2}{T_1T_2}\)

\(\frac{P_1T_1 + P_2T_2}{T_1T_2}\)

None of these 

Correct Answer:

\(\frac{P_1T_2 + P_2T_1}{2T_1T_2}\)

Explanation:

Given : \(\frac{P_1}{P_2} = \frac{n_1 T_1}{n_2 T_2}\)

P \(\propto \) nT.

It implies that volume of both containers is same. After mixing.

P(2V) = (n1 + n2)RT

P(2V) = (\(\frac{P_1V}{RT_1} + \frac{P_2V}{RT_2}\))Rt

\(\frac{P}{T} = \frac{1}{2} (\frac{P_1}{T_1} + \frac{P_2}{T_2})\)

\(\frac{P}{T} = \frac{1}{2} (\frac{P_1T_2 + P_2T_1}{T_1T_2})\)