A man of 60 kg weight is standing at rest on a platform. He jumps up vertically a distance of 1 m and the platform at the same instant moves horizontally forward with the result that the man lands 1 meter behind the point on the platform from where the took the jump the total work done by the man at the instant he lands is :
Answer & explanation
Correct answer: option 2
Work done : \(W = F * S\)
\(W = mg * S\)
\(W = 60*10*1\)
\(W = 600 \text{ J}\)