Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Work Power Energy

Question:

A man of 60 kg weight is standing at rest on a platform. He jumps up vertically a distance of 1 m and the platform at the same instant moves horizontally forward with the result that the man lands 1 meter behind the point on the platform from where the took the jump the total work done by the man at the instant he lands is : 

Options:

1200 J

600 J

300 J

100 J

Correct Answer:

600 J

Explanation:

Work done : \(W = F * S\)

\(W = mg * S\)

\(W = 60*10*1\)

\(W = 600 \text{ J}\)