What is the expansion of $(1-\frac{1}{p})^2$ ?
Answer & explanation
Correct answer: option 2
( a - b )2 = a2 + b2 - 2ab
$(1-\frac{1}{p})^2$ = 12 + \(\frac{1}{p^2}\) - 2 × 1 × \(\frac{1}{p}\)
= $(1-\frac{1}{p})^2$ = $ 1-\frac{2}{p} +\frac{1}{p^2}$
What is the expansion of $(1-\frac{1}{p})^2$ ?
Correct answer: option 2
( a - b )2 = a2 + b2 - 2ab
$(1-\frac{1}{p})^2$ = 12 + \(\frac{1}{p^2}\) - 2 × 1 × \(\frac{1}{p}\)
= $(1-\frac{1}{p})^2$ = $ 1-\frac{2}{p} +\frac{1}{p^2}$