\(x=\int_{0}^{y}\frac{1}{\sqrt{1+9t^2}}dt\) and \(\frac{d^2y}{dx^2}=ay\). Then \(a=\)
Answer & explanation
Correct answer: option 3
By Leibnitz rule \(\frac{dx}{dy}=\frac{1}{\sqrt{1+9y^2}}\)
\(\frac{d^2y}{dx^2}=9y\)
\(x=\int_{0}^{y}\frac{1}{\sqrt{1+9t^2}}dt\) and \(\frac{d^2y}{dx^2}=ay\). Then \(a=\)
Correct answer: option 3
By Leibnitz rule \(\frac{dx}{dy}=\frac{1}{\sqrt{1+9y^2}}\)
\(\frac{d^2y}{dx^2}=9y\)