In △ABC, D and E are the points on sides AB and AC, respectively and DE ∥ BC. BC = 8 cm and DE = 5 cm. If the area of △ADE = 45 cm2, then what is the area (in cm2) of △ABC ?
Answer & explanation
Correct answer: option 1
Calculations
Length of DE = 5 cm
Therefore, Area of ADE is \( {5 }^{2 } \) = 25
Length of BC = 8 cm
Therefore, Area of BC is \( {8 }^{2 } \) = 64
According to the question
= 25 = 45
Therefore, 64 = \(\frac{45 \;×\; 64}{25}\)
Therefore, area of \(\Delta \)ABC is 115.2 cm.