Chords AB and CD of a circle intersect externally at P. If CD = 11.6 cm, PD = 6.4 cm and PB = 7.2 cm, then AB (in cm) is equal to:
Answer & explanation
Correct answer: option 3
A detailed explanation for this question is coming soon.
Chords AB and CD of a circle intersect externally at P. If CD = 11.6 cm, PD = 6.4 cm and PB = 7.2 cm, then AB (in cm) is equal to:
Correct answer: option 3
A detailed explanation for this question is coming soon.