AB is a diameter of a circle with centre

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Target Exam

CUET

Subject

General Test

Chapter

Quantitative Reasoning

Topic

Geometry

Question:

AB is a diameter of a circle with centre O, and P is a point on the circle. If ∠POA = 130°, then ∠PBO is equal to:

Options:

60°

55°

65°

45°

Correct Answer:

65°

Explanation:

We know that,

∆ POB = ∠P = ∠B ( Isosceles triangle )

and ∠POA is double of ∠PBO ( external angle property)

So the value of ∠PBO is = \(\frac{130}{2}\) = 65^o