AB is a diameter of a circle with centre O, and P is a point on the circle. If ∠POA = 130°, then ∠PBO is equal to:
Answer & explanation
Correct answer: option 3
We know that,
∆ POB = ∠P = ∠B ( Isosceles triangle )
and ∠POA is double of ∠PBO ( external angle property)
So the value of ∠PBO is = \(\frac{130}{2}\) = 65o